This is another post in my ``psuedo-daily'' series ``What I learned Today''
Yesterday we talked about actions of a Hopf algebra H on an algebra A. Today, let's talk about some examples of this (I didn't cover as much ground as I hoped to today, but we're trying to make these blogs daily!). Every Hopf algebra acts on itself by
\displaystyle h \triangleright g = \sum_h h_{(1)} g Sh_{(2)}
This is the adjoint action. It's not hard to prove that it's 1) an action and 2) a Hopf action (that it plays well with the Hopf algebra structure of H and the algebra structure of A). As a more concrete example, let's look at the group Hopf algebra H=kG for a finite group G. The coproduct is given by \Delta g = g \otimes g and the antipode is group inversion: Sg = g^-1. In this case, the adjoint action becomes:
\displaystyle h \triangleright g = hgh^{-1}
Which is just group conjugation.
Hopf algebras can act just as well on coalgebras - in this case we require that the action commutes with the coproduct of A. Now if H' and H are dually paired, then we also have adjoint action, or rather, a coadjoint action of H' on the coalgebra H, given by:
\displaystyle \phi \triangleright h = \sum_h h_{(2)} \langle \phi, (Sh_{(1)})h_{(3)} \rangle
We know that the algebra of functions on G, k(G) is the Hopf algebra dual of kG, where \langle f, g \rangle = f(g), so let's see what the this action becomes for H' = k(G) and H = kG:
\displaystyle f \triangleright g = g \langle f, (Sg)g \rangle = f(1) \cdot g
Additionally, we also have the notion of a coaction. Generally, if H is a Hopf algebra and A an algebra, we say \beta : A \rightarrow H \otimes A is a coaction of H on A (or that A is a H-comodule algebra if \beta is a algebra morphism, (I \otimes \beta) \circ \beta = (\Delta \otimes I) \circ \beta and I = (\epsilon \otimes I) \circ \beta, where I is the identity and \Delta and \epsilon are the coalgebra structure maps.
The most interesting case of this is the quantum group SL_q(2) coacting on the quantum plane \mathbb{A}^2_q. This is a topic for another post, though.
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